Ask a New Question

The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−A/r^m+B/r^n

Derive and expression for the stiffness of the bond at the equilibrium spacing, in terms of A, B, m, n, and r0.
S=dF/dr at r=r0:

1 answer

I don't know what F is, but

dU/dr = Am/r^(m+1) - Bn/r^(n+1)
So, plug in r0 and you have

dU/dr(r0) = Am/r0^(m+1) - Bn/r0^(n+1)

Ask a New Question or answer this question.

Similar Questions

The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−Arm+Brn1) Derive an expression for the equilibrium
1. 1 answer
The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−A/r^m+B/r^nDerive an expression for the equilibrium
1. 0 answers
The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−A/r^m+B/r^nDerive and expression for the stiffness
1. 2 answers
The energy-separation curve for two atoms, a distance, r, apart is: U(r)=−A/r^m+B/r^nfirst I have: ((A*m)/(B*n))^(1/(m-n))
1. 1 answer

more similar questions