The energy of the em waves is of the order of 15 kev.to which part of the spectrum does it belong?
3 answers
google electromagnetic spectrum energy
E = h f
= 6.626 *10^-34 f Joules
1 ev = 1.6 * 10^-19 J
so E is 15*10^3 *1.6*10^-19 J
= 24 * 10^-16 Joules
so
24 * 10^-16 = 6.626*10^-34 f
f = 3.62 * 10^18 Hz
now go look at your spectrum
if it is by wavelength
lambda = 3*10^8/(3.62*10^18)
= .828 * 10^-10
= 8.28 * 10^-11 meters
= 6.626 *10^-34 f Joules
1 ev = 1.6 * 10^-19 J
so E is 15*10^3 *1.6*10^-19 J
= 24 * 10^-16 Joules
so
24 * 10^-16 = 6.626*10^-34 f
f = 3.62 * 10^18 Hz
now go look at your spectrum
if it is by wavelength
lambda = 3*10^8/(3.62*10^18)
= .828 * 10^-10
= 8.28 * 10^-11 meters
Xray or Gamma ray
1 answer