Heat lost=heat gained
300*c*50=300*4.18*10
The energy given off by 300 grams of an alloy as it cools through 50°C raises the temperature of 300 grams of water from 30°C to 40°C. The specific heat of the alloy (in cal/g C ) is:
i know Q=CpM(delta T)
but what is what?
2 answers
50