The elevation of city A is 80 feet below sea level; the elevation of city C is 16 feet below sea level. The elevation of city D is 1 over 2 of the elevation of city C.

Question

Part A: Write an expression to represent the elevation, in feet, of city D. (5 points)

Part B: Solve the expression and explain why the answer is negative or positive. (5 points)

Answer 1

Part A: The expression to represent the elevation of city D is $\frac{1}{2} \times$ the elevation of city C.

Part B: To solve the expression, we need to know the elevation of city C. Given that city C is 16 feet below sea level, the expression becomes $\frac{1}{2} \times (-16)$.

The answer is negative because both the elevation of city C and the coefficient $\frac{1}{2}$ in the expression are negative. When we multiply a negative number by a positive number, the result is negative. Thus, the elevation of city D is negative.

Answer 2

I did not understand couuld you make it in human terms

Answer 3

Sure! Let's break it down in simpler terms.

Part A: The expression to represent the elevation of city D is half of the elevation of city C.

Part B: To find the elevation of city D, we need to know the elevation of city C. Given that city C is 16 feet below sea level, we can calculate the elevation of city D as follows:

Elevation of city D = (1/2) * Elevation of city C

Since the Elevation of city C is negative (16 feet below sea level), when we multiply it by (1/2), the result is still negative. Therefore, the elevation of city D is also negative.

Answer 4

The temperature of a city changed by a total of −20 degrees Celsius over a 4-week period. The temperature changed by the same amount each week.

Part A: Write an expression to show the average change in the temperature of the city each week. (5 points)

Part B: Simplify the expression and explain, using words, what your answer means. (5 points)

Answer 5

Part A: The expression to show the average change in temperature of the city each week can be represented as -20 degrees Celsius divided by 4 weeks.

Part B: Simplifying the expression, we have (-20 degrees Celsius) ÷ 4 weeks, which equals -5 degrees Celsius per week.

This means that on average, the temperature of the city decreased by 5 degrees Celsius each week over the 4-week period. The negative sign indicates a decrease in temperature.

Answer 6

write the temperature of a city changed by a total of −20 degrees Celsius over a 4-week period. The temperature changed by the same amount each week.

Part A: Write an expression to show the average change in the temperature of the city each week. (5 points)

Part B: Simplify the expression and explain, using words, what your answer means. (5 points)

Answer 7

Part A: The expression to show the average change in temperature of the city each week can be represented as $\frac{-20}{4}$ degrees Celsius per week.

Part B: Simplifying the expression, we have $-5$ degrees Celsius per week.

This means that, on average, the temperature of the city decreased by 5 degrees Celsius each week over the 4-week period. The negative sign indicates a decrease in temperature.

Answer 8

bot can you write it in humann

Answer 9

Of course! Let's break it down in simpler terms.

Part A: The expression to show the average change in temperature of the city each week is "-20 degrees Celsius divided by 4 weeks".

Part B: Simplifying the expression, we have "-5 degrees Celsius per week".

This means that, on average, the temperature of the city decreased by 5 degrees Celsius each week over the 4-week period. The negative sign indicates that the temperature decreased.

Answer 10

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Mark simplified three over five ÷ five over eight; his work is shown below. Identify where he made his error. (5 points)

Original division problem: three over five ÷ five over eight

Step 1: three over five multiplied by eight over five

Step 2:three times eight over five times five

Step 3:twenty-four over five

Step 4:four and four over five

Step 1

Step 2

Step 3

Step 4

Answer 11

The error made by Mark can be identified in Step 2.

Step 2 should be: Three times eight over five.

However, Mark mistakenly wrote: Three times eight over five times five.

By multiplying the denominators together, Mark incorrectly changed the division operation into a multiplication operation.