The electronegativities of the elements are H=2.1, O=3.5, F=4.0, S=2.5, Cl=3.0. Determine (calculate) the electronegativity diffrences for the following molecules and explain how they are arranged in the order: H2, O2, HCl, HF, H2O and position them in the following designations.

Question

Covalent bond-Polar Covalent Bond-Polar Bond. I have tried this question countless times and need help on how to calculate and determine the answers.

Answer 1

You are making it harder than it really is.
For H2 it is 2.1-2.1 = 0, right?
For O2 it is 3.5-3.5 = 0, right?
For HCl it is 3.5-2.1 = 1.4, right?
For HF it is 4.0 - 2.1 = 1.9 etc
A difference of zero makes it as near covalent as we can get.
A difference of 1.9 or so (some profs call it 1.7 and some 2.0) you have approximately 50/50 covalent-ionic bond. Anything over that is called ionic(polar), anything between that and zero is called polar covalent.

Answer 2

The compound of Na