ax²+bx+c=0,
14x²-19 x +61 =0,
x= [19±sqrt{19²+4•14•61}]/2•14 =
=(19±61.5)/28.
x₁=2.88 m,
x₂=-1.52 m
The electric potential in a certain region is
V = a x2 + b x + c,
where a = 14 V/m2, b = −19 V/m, and c = 61 V.
Determine the position where the electric field is zero.
Answer in units of m
Please help!
1 answer