The electric potential energy stored in the capacitor of a defibrillator is 83 J, and the capacitance is 124 µF. What is the potential difference that exists across the capacitor plates?

_____________ V

1 answer

W =0.5CV^2 = 83 Joules.
0.5 * 124*10^-6 * V^2 = 83,
62*10^-6 * V^2 = 83,
V^2 = 83 / 62*10^-6 = 1.3887*10^6,
V = sqrt(1.3887*10^6)
V = 1.1570*10^3 = 1157 Volts.