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The efficiency of a machine is 80%. Determine the work done by a person using this machine to raise a load of 200kg through a vertical distance of 3.0 (take g = 10m/s)

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F = M*g = 200 * 10 = 2000 N.

Work = F*d/0.8 = 2000 * 3/0.8 =

7500Joules

7500 joules

7500

7500

7500 joules

7500joules

7500 Joules

7500 joules

7500joules

7500

7500 Joule

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