the effective resistacce of two resistors connected in series is 100 ohm.when it connected in parallel it is 24 ohm.determine the values of two resistors

1 answer

R+r=100
1/R +1/r =1/24 => (R+r)/Rr=1/24

100/Rr =1/24
rR=2400

Since r=100-R
R(100-R)=2400
R²-100R+2400=0
R=40 Ω => r=60 Ω
R=60 Ω => r=40Ω