acceleration = e E/m.
e = 1.6*10^-19 C
m = 9.1*10^-31 kg
E = 150 N/C
I do not agree with your answer.
The Earth is surrounded by an electric field on its surface that points toward the center of the Earth with an average magnitude of 150 N/C. If there is an electron that is released in vacuum at the Earth’s surface, what will the acceleration due to the Earth’s electric field be.
I got 2.6 × 1013 m/s2 am I right
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