The driver of a car traveling at 60 ft/sec suddenly applies the brakes. The position of the car is s(t) equals 60t minus - 1.5t^2, t seconds after the driver applies the brakes. How many seconds after the driver applies the brakes does the car come to a stop?

Answer 1

the initial velocity is 60 ft/s

s = 60t - 1/2 at^2
So, a = 3 ft/s^2
60/3 = 20 seconds

I wouldn't call that a sudden stop!