The driver of a Cadillac is traveling at a constant 60mi/hr. A police car is 20m behind the perpetrator when it too reaches 60 mi/hr and at that moment the officer floors the gas pedal.

If the police car roars up to the rear of the Cadillac 2.0s later what was its acceleration, assuming it to be constant?

1 answer

V=60mi/h * 1600m/mi*1h/3600s.=26.67m/s

d2 = d1 + 20 m
Vo*t + 0.5a*t^2 = V1*t + 20
26.67*2 + 0.5a*2^2 = 26.67*2 + 20
53.33 + 2a = 73.33
2a = 20
a = 10 m/s^2.