Looking at your figure, is it apparent that
Fx = F sin alpha cos beta
Fy = F sin alpha sin beta
Fz = F cos alpha
Thanks for writing out the website of the figure so that it would not be blocked by Jiskha software.
The drawing shows a force vector vector F that has a magnitude of 600 newtons. It lies at alpha = 67° from the positive z axis, and beta = 31° from the positive x axis.
(that's the diagram given)
webassign. (delete this space) net/CJ/p1-39alt.gif
(a) Find the x component of the vector vector F .
(blank) m
(b) Find the y component of the vector vector F .
(blank) m
(c) Find the z component of the vector vector F .
(blank) m
1 answer