A system of equations can be set up to represent the problem:
s = number of student tickets sold
a = number of adult tickets sold
s + a ≤ 122 (maximum number of people who can attend)
5s + 9a ≥ 890 (minimum amount of money needed)
Substitute s = 45 into the second equation and solve for a:
5(45) + 9a ≥ 890
225 + 9a ≥ 890
9a ≥ 665
a ≥ 73.9
Since a must be a whole number, the drama club must sell at least 74 adult tickets to meet the show's expenses.
The drama club is selling tickets to their play to raise money for the show's expenses.
Each student ticket sells for $5 and each adult ticket sells for $9. The auditorium can
hold a maximum of 122 people. The drama club must make no less than $890 from
ticket sales to cover the show's costs. If 45 student tickets were sold, determine the
minimum number of adult tickets that the drama club must sell in order to meet the
show's expenses. If there are no possible solutions, submit an empty answer.
Answer:
1 answer
1 answer