Cats, because the range of their weights is less than that of small dogs.
This is because the dot plot for cats shows a narrower distribution of weights, with the dots clustered closer together compared to the dot plot for small dogs, which shows a wider spread of weights. This indicates that there is less variability in the weights of cats compared to small dogs.
The dot plots show the weights of randomly selected cats and small dogs in different households.
Based on an informal assessment of the visual overlap of these distributions, which animal has the least variability in their weights? Why?
• Cats, because the range of their weights is greater than that of small do
• Cats, because the range of their weights is less than that of small dogs.
• Small dogs, because the range of their weights is greater than that of cats
• Small dogs, because the range of their weights is less than that of cats.
11 answers
The dot plots show the weights of randomly selected cats and small dogs in different households.
What is the difference between the modal weights of cats and small dogs?
1 pound
0.13 pounds
The modal weights are the same for cats and small dogs
3 pounds
What is the difference between the modal weights of cats and small dogs?
1 pound
0.13 pounds
The modal weights are the same for cats and small dogs
3 pounds
The modal weights are the same for cats and small dogs.
This is because both dot plots show one clear peak where the majority of the weights are concentrated, indicating that there is one mode for both cats and small dogs.
This is because both dot plots show one clear peak where the majority of the weights are concentrated, indicating that there is one mode for both cats and small dogs.
The data shows the number of miles run per week by randomly selected students from two different classes. Find the difference between the medians. Which class has a higher median?
By how much?
Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11
Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
(1 point)
• Class 2 has a higher median than Class 1 by 1 mile.
•.
Class 2 has a higher median than Class 1 by 0.5 mile.
• Class 1 has a higher median than Class 2 by 1 mile.
• Class 1 has a higher median than Class 2 by 0.5 mile.
By how much?
Class 1: 6, 8, 10, 11, 14, 4, 5, 8, 2, 7, 7, 5, 10, 12, 11
Class 2: 6, 4, 5, 6, 7, 8, 12, 9, 10, 11, 5, 8, 7, 4, 10
(1 point)
• Class 2 has a higher median than Class 1 by 1 mile.
•.
Class 2 has a higher median than Class 1 by 0.5 mile.
• Class 1 has a higher median than Class 2 by 1 mile.
• Class 1 has a higher median than Class 2 by 0.5 mile.
To find the medians for each class, we first need to sort the data in ascending order:
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Median for Class 1: 8
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Median for Class 2: 7
The difference between the medians is 8 - 7 = 1 mile.
Therefore, Class 1 has a higher median than Class 2 by 1 mile.
Class 1: 2, 4, 5, 5, 6, 7, 7, 8, 8, 10, 10, 11, 11, 12, 14
Median for Class 1: 8
Class 2: 4, 4, 5, 5, 6, 6, 7, 7, 8, 8, 9, 10, 10, 11, 12
Median for Class 2: 7
The difference between the medians is 8 - 7 = 1 mile.
Therefore, Class 1 has a higher median than Class 2 by 1 mile.
Two fertilizers are applied to randomly selected potato plants. After several weeks, the potatoes are weighed. The weights in kilograms are as follows. Which fertilizer is generally more effective?
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
(1 point)
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same
Fertilizer A: 27, 20, 16, 18, 22, 19, 23, 21, 17, 19
Fertilizer B: 28, 19, 18, 21, 24, 20, 25, 27, 29, 21
(1 point)
Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer A is generally more effective, because the mean and median weights of the potatoes treated with it are higher.
Fertilizers A and B are both ineffective, because there is no difference in the ranges of the weights of the potatoes.
Fertilizers A and B are equally effective, because the ranges of the weights of the potatoes are the same
To determine which fertilizer is generally more effective, we can compare the mean and median weights of the potatoes treated with each fertilizer:
Fertilizer A: Mean = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 20.2 kg
Median = 19.5 kg
Fertilizer B: Mean = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 22.2 kg
Median = 21 kg
From the calculations, we can see that Fertilizer B has both a higher mean weight and a higher median weight compared to Fertilizer A. Therefore, Fertilizer B is generally more effective.
The correct answer is: Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
Fertilizer A: Mean = (27 + 20 + 16 + 18 + 22 + 19 + 23 + 21 + 17 + 19) / 10 = 20.2 kg
Median = 19.5 kg
Fertilizer B: Mean = (28 + 19 + 18 + 21 + 24 + 20 + 25 + 27 + 29 + 21) / 10 = 22.2 kg
Median = 21 kg
From the calculations, we can see that Fertilizer B has both a higher mean weight and a higher median weight compared to Fertilizer A. Therefore, Fertilizer B is generally more effective.
The correct answer is: Fertilizer B is generally more effective, because the mean and median weights of the potatoes that were treated with it are higher.
For a geography project, you have surveyed the people in your hiking club and swimming club to find the number of states they have visited. You make a table and dot plots to show the results.
Use the dot plots to compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
Use the dot plots to compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
Based on the dot plots of the number of states visited by the people in your hiking club and swimming club, you can draw the following conclusions about the shapes and spreads:
Shapes:
1. If the dot plot for the hiking club is more symmetrical with a roughly equal distribution of dots on both sides of the center line, while the dot plot for the swimming club is skewed to one side, it can be inferred that there may be more people in the hiking club who have visited a similar number of states, while in the swimming club, there may be a few individuals who have visited a significantly higher number of states compared to the majority.
2. If the dot plots for both clubs are roughly symmetrical, it suggests that the distribution of the number of states visited is similar for both clubs.
Spreads:
1. If the dots in the dot plot for the hiking club are more spread out along the number line, it indicates a wider range of states visited compared to the swimming club. Conversely, if the dots in the dot plot for the swimming club are more tightly clustered, it suggests that the majority of individuals in the swimming club have visited a similar number of states.
2. If both dot plots show a similar spread, it suggests that both clubs have a similar range of states visited by their members.
In summary, by comparing the shapes and spreads of the dot plots, you can draw conclusions about the distribution of the number of states visited by the members of the hiking club and swimming club.
Shapes:
1. If the dot plot for the hiking club is more symmetrical with a roughly equal distribution of dots on both sides of the center line, while the dot plot for the swimming club is skewed to one side, it can be inferred that there may be more people in the hiking club who have visited a similar number of states, while in the swimming club, there may be a few individuals who have visited a significantly higher number of states compared to the majority.
2. If the dot plots for both clubs are roughly symmetrical, it suggests that the distribution of the number of states visited is similar for both clubs.
Spreads:
1. If the dots in the dot plot for the hiking club are more spread out along the number line, it indicates a wider range of states visited compared to the swimming club. Conversely, if the dots in the dot plot for the swimming club are more tightly clustered, it suggests that the majority of individuals in the swimming club have visited a similar number of states.
2. If both dot plots show a similar spread, it suggests that both clubs have a similar range of states visited by their members.
In summary, by comparing the shapes and spreads of the dot plots, you can draw conclusions about the distribution of the number of states visited by the members of the hiking club and swimming club.
For a geography project, you have surveyed the people in your hiking club and swimming club to find the number of states they have visited. You make a table and dot plots to show the results.
Use the dot plots to compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10.
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has peaks at 9 and 10. The swimming club has a peak at 5
The hiking club has a greater spread than the swimming club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10.
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed right. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10
Use the dot plots to compare the shapes and spreads of the dot plots. What conclusions can you draw about the shapes and the spreads?
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10.
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has peaks at 9 and 10. The swimming club has a peak at 5
The hiking club has a greater spread than the swimming club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10.
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed right. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10
The swimming club has a greater spread than the hiking club. The hiking club is symmetrical, and the swimming club is skewed left. The hiking club has a peak at 5. The swimming club has peaks at 9 and 10.
This conclusion is drawn based on the information provided about the shapes, spreads, peaks, and skewness of the dot plots for the hiking club and swimming club.
This conclusion is drawn based on the information provided about the shapes, spreads, peaks, and skewness of the dot plots for the hiking club and swimming club.
5 answers