The domain of logarithmic function f(x)=lnx

is x>0
. Which statement is true about its corresponding exponential function g(x)=ex
?(1 point)
Responses

Function g(x)
has a range of y≤0
.
Function g left parenthesis x right parenthesis has a range of y less-than-or-equal-to 0 .

Function g(x)
has a range of y>0
.
Function g left parenthesis x right parenthesis has a range of y greater than 0 .

Function g(x)
has a domain of x≤0
.
Function g left parenthesis x right parenthesis has a domain of x less-than-or-equal-to 0 .

Function g(x)
has a domain

1 answer

To determine the characteristics of the exponential function \( g(x) = e^x \), we can draw from the properties of logarithmic and exponential functions.

  1. Domain of \( g(x) \):
    The exponential function \( g(x) = e^x \) is defined for all real numbers. Therefore, the domain of \( g(x) \) is \( x \in (-\infty, \infty) \).

  2. Range of \( g(x) \):
    The output of the exponential function \( e^x \) is always positive as \( e^x > 0 \) for all real \( x \). Thus, the range of \( g(x) \) is \( y > 0 \).

Given the above points, the correct statement about the corresponding exponential function \( g(x) \) is:

Function \( g(x) \) has a range of \( y > 0 \).

Hence, the correct response is:

Function g(x) has a range of y>0.