The divisor and qutient of the number 6123 are same andthe remainder is half of the divisor. Find the divisor.
2 answers
What is the square root of 6123?
6123/x = x + (1/2)x/x
times x
6123 = x^2 + (1/2)x
times 2
2x^2 + x - 12246 = 0
(x - 78)(2x + 157) = 0
x = 78 or x = -157
check:
6123/78 = 78 + remainder of 39 , which is 1/2 of 78
6123/-157 ≠ -157 + (????)
the divisor is 78
times x
6123 = x^2 + (1/2)x
times 2
2x^2 + x - 12246 = 0
(x - 78)(2x + 157) = 0
x = 78 or x = -157
check:
6123/78 = 78 + remainder of 39 , which is 1/2 of 78
6123/-157 ≠ -157 + (????)
the divisor is 78