The distribution of heights of women aged 20 to 29 is approximately normal with a mean of 2.8 inches and standard deviation of 2.8 inches. The height (+/- 0.1 inch) of the middle 99.7% falls between a low of ?? inches and a high of ?? inches.
Please help on how I set this up to find the answer.
2 answers
sorry. its 62.8 for the mean
.997 = mean ± Z * SD
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.003/2) and its Z score. Insert data into above equation and solve.
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability (.003/2) and its Z score. Insert data into above equation and solve.
1 answer