To find the height of the cylindrical candle, we can use the formula for the volume of a cylinder:
\[ V = \pi r^2 h \]
where:
- \( V \) is the volume,
- \( r \) is the radius,
- \( h \) is the height.
From the problem, we know:
- The distance from the wick to the edge of the candle is 2 inches, which means the radius (\( r \)) of the candle is 2 inches.
Thus, we can set \( r = 2 \) inches, and we know the volume \( V = 159 \) cubic inches. Now we can substitute these values into the volume formula and solve for \( h \):
\[ 159 = \pi (2^2) h \] \[ 159 = \pi (4) h \] \[ 159 = 4\pi h \] \[ h = \frac{159}{4\pi} \]
Now we need to calculate \( h \):
\[ h = \frac{159}{4 \times 3.14159} \approx \frac{159}{12.56636} \approx 12.65 \]
Rounding to the nearest whole number gives us:
\[ h \approx 13 \]
Thus, if the options provided were:
- 1
- 124
- 23
- 22
- 10
and none of them match our calculation, it seems there might be a misunderstanding or miscommunication about either the options or the measurements provided. Please verify the options again. Based on our calculation, the height is approximately 13 inches.
1 answer