The distance of a port from 20 different locations form an AP.if the farthest distance is 300km, and the nearest distance is 30km, what is the distance between any two successive locations?

Answer 1

In this A.P. distances are:

a , a + r , a + 2 r ... , a + 19 r

where a is the distance of the nearest location from the port and r is the difference between any two successive location.

In this case a =30 km

The farthest distance is 300 km

The farthest distance is 20th term of A.P.

a20 = a + 19 r

a + 19 r = 300

30 + 19 r = 300

19 r = 300 - 30

r = 270 /19 km

270 / 19 km is the distance between any two successive location.