The distance (in feet) of an object from a point is given by s(t)=3t^(2)−5, where t is in seconds. Round your answer to two decimal places.

Question

1. What is the average velocity of the object between t=1 and t=8.5?
2. By using smaller and smaller intervals around 1, estimate the instantaneous velocity at time t=1.

Answer 1

#1. That would be (s(8.5) - s(1))/(8.5 - 1)
#2. You can start with ∆t = 0.1
(s(1.1) - s(1)) / (1.1 - 1)
and decrease the ∆t

Answer 2

Thank you so much!! Great help!!