We can set up a proportion to solve this problem.
Since the distance, d, is directly proportional to the square of the time, t, we can write the proportion as:
d₁/t₁² = d₂/t₂²
where d₁ is the distance the object has fallen in t₁ seconds, and d₂ is the distance we want to find in t₂ seconds.
We are given that the object has fallen 144 feet in 3 seconds, so we have:
144/3² = d₂/4²
Simplifying, we get:
144/9 = d₂/16
Cross multiplying, we have:
9 * d₂ = 144 * 16
Solving for d₂, we get:
9 * d₂ = 2304
d₂ = 2304/9 ≈ 256
Therefore, if the object has been falling for 4 seconds, it would have fallen approximately 256 feet.
The distance, d, that an object falls is directly proportional to the square of the time, t, it has been in free fall. An object that has been in free fall for 3 seconds has fallen 144 feet. Determine the distance the object has fallen if it has been falling for 4 seconds.
d = ? ft
1 answer