The distance between a concave mirror and an object placed I front of it is 1•0m. If the radius of curvature of the minor is 4•0m, the image formed will be?

Answer 1

To determine the type and properties of the image formed, we can use the mirror equation:

1/f = 1/v - 1/u,

where f is the focal length of the mirror, v is the image distance, and u is the object distance.

Given:
u = 1.0 m,
f = R/2 = 4.0 m / 2 = 2.0 m.

By substituting these values into the mirror equation, we can solve for the image distance:

1/2.0 = 1/v - 1/1.0.
1/2.0 = 1/v - 1.
1/v = 1 - 1/2.0 = 1/2.0.
v = 2.0 m.

Therefore, the image distance is v = 2.0 m.

To determine the type of image formed, we can now use the magnification equation:

m = -v/u,

where m is the magnification.

m = -2.0/1.0 = -2.0.

Since the magnification is negative, the image formed by the concave mirror is real, inverted, and diminished.