Question

The distance between (-7;y) and (-3;4) is 5,66

Answer 1

To find the distance between two points (-7, y) and (-3, 4), we can use the distance formula:

Distance = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In this case:
x1 = -7
y1 = y
x2 = -3
y2 = 4

Substitute these values into the formula:

Distance = sqrt((-3 - (-7))^2 + (4 - y)^2)
Distance = sqrt((-3 + 7)^2 + (4 - y)^2)
Distance = sqrt(4^2 + (4 - y)^2)
Distance = sqrt(16 + (4 - y)^2)
Distance = sqrt(16 + 16 - 8y + y^2)

Since we know that the distance is equal to 5.66, we can solve for y:

5.66 = sqrt(32 - 8y + y^2)
31.9356 = 32 - 8y + y^2
0 = y^2 - 8y + 0.0644

We can solve this quadratic equation using the quadratic formula. But because the term 8y is squared we cannot determine the exact value of y.