Asked by Ramesh
                The discrete random variable W has probability density function (p.d.f.) given by:
P(W=w) = c(5-w) for w= 0, 1, 2, 3
Find c
I honestly have no idea how to start Any help is appreciated.
Thanks.
            
        P(W=w) = c(5-w) for w= 0, 1, 2, 3
Find c
I honestly have no idea how to start Any help is appreciated.
Thanks.
Answers
                    Answered by
            Steve
            
    the probabilities must add up to 1. So,
c(5-0)+c(5-1)+c(5-2)+c(5-3) = 1
5c+4c+3c+2c = 1
c = 1/14
    
c(5-0)+c(5-1)+c(5-2)+c(5-3) = 1
5c+4c+3c+2c = 1
c = 1/14
                    Answered by
            Damon
            
    well, if that is the whole distribution, they have to add up to 1
5 c +4 c + 3 c + 2 c = 1
    
5 c +4 c + 3 c + 2 c = 1
                    Answered by
            Ramesh
            
    Oh wow it was a lot easier than I thought...
Thanks so much!
    
Thanks so much!
                    Answered by
            Damon
            
    You are welcome.
    
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