The last two digits will need to be divisible by 4.
That means we may have
12,16
24
32,36
44
52,56
64
Or, 9 possible 2-digit endings
Since there are 6*5 = 30 total endings, there is a 30% chance that the number is divisible by 4.
The digits 1,2,3,4,5,6 are arranged to form a 6-digit number.What is the probability that the number formed is divisible by 4?
1 answer
1 answer