The diffusion rate for a solute is 4.0 10-11 kg/s in a solvent-filled channel that has a cross-sectional area of 0.50 cm2 and a length of 0.220 cm. What would be the diffusion rate m/t in a channel with a cross-sectional area of 0.30 cm2 and a length of 0.10 cm?

Answer 1

rate is proportional to area and inversely proportional to length

4 * 10*-11 kg/s = k * .5cm^2 /.22
k = 1.76 * 10^-11

rate = 1.76*10^-11*.3/.1

= 5.28 * 10^-11 kg/s

Answer 2

Thank you, Damon. :)