The differential of the function y=(x^2+6)^3 is

dy=______dx.
When x=2 and dx=0.05, the differential dy=_______?

A) dy=______dx?
B) the differential dy=_______?

1 answer

dy/dx = 3(x^2 + 6)^2

dy = 3(x^2 + 6)^2 dx
when x = 2 and dx = .05

dy = ......

just plug in the above values.