the difference of two numbers is 32 and their quotient is 3. what is this number?

Answer 1

Let's call the two numbers x and y.

Given that the difference of the two numbers is 32, we can set up the equation:
x - y = 32

Given that their quotient is 3, we can set up the equation:
x / y = 3

Now, we can solve these two equations simultaneously to find the values of x and y.

From the second equation, we can rearrange it to get:
x = 3y

Substitute this into the first equation:
3y - y = 32
2y = 32
y = 16

Now, substitute the value of y back into the equation x = 3y:
x = 3(16)
x = 48

Therefore, the two numbers are 48 and 16.

Answer 2

are you sure?

Answer 3

Let's reevaluate the problem to ensure accuracy:

Let the two numbers be x and y. We are given that the difference of the two numbers is 32:

x - y = 32

We are also given that the quotient of the two numbers is 3:

x / y = 3

From the second equation, we can rewrite it as:

x = 3y

Substitute this value of x into the first equation:

3y - y = 32
2y = 32
y = 16

Now, substitute the value of y back into the equation x = 3y:

x = 3(16)
x = 48

Therefore, the two numbers are 48 and 16.

Answer 4

thats not right

Answer 5

Apologies for the error. Let's reevaluate the problem:

Let's denote the two numbers as x and y. We are given that the difference of the two numbers is 32:

x - y = 32

We are also given that the quotient of the two numbers is 3:

x / y = 3

To solve this system of equations, we can rearrange the second equation to x = 3y, and then substitute it into the first equation:

3y - y = 32
2y = 32
y = 16

Substitute the value of y back into x = 3y:

x = 3(16)
x = 48

Therefore, the two numbers are 48 and 16. Apologies for the oversight in the previous responses.