x-y = 6
x + 2y = 72
subtract them:
3y = 66
y = 22
then
x-22 = 6
x = 28
the two numbers are 22 and 28
so "the sum of 3 times the larger and 2"
= 3(28) + 2 = 86
You claim your answer is:
192 and 72
Is their difference equal to 6 ????
The difference of two integers is 6. The sum of twice the smaller and the larger is 72. Find the integers.
The sum of 3 times a larger integer and 2
my answer the lager integer is 192 and the smaller integer is 72
2 answers
12 and 6
2 answers