Let's call the smaller number s and the larger number l.
According to the problem:
1. l - s = 31
2. s = 2l - 38
We can now substitute the second equation into the first equation to solve for the two numbers:
l - (2l - 38) = 31
l - 2l + 38 = 31
-1l + 38 = 31
-1l = -7
l = 7
Now we can substitute the value of l back into the second equation to find s:
s = 2(7) - 38
s = 14 - 38
s = -24
Therefore, the smaller number is -24 and the larger number is 7.
The difference between two numbers is 31. The smaller number is 38 less than twice the larger number. Find the two numbers.
The smaller number is __. The larger number is __.
1 answer