Let's call the larger number x and the smaller number y.
Given that the difference between two numbers is 31, we can write the equation:
x - y = 31
And since the smaller number y is 38 less than twice the larger number x, we can write another equation:
y = 2x - 38
Now we can substitute the second equation into the first equation to solve for x:
x - (2x - 38) = 31
x - 2x + 38 = 31
-x + 38 = 31
38 = x + 31
x = 7
Now that we have found the value of x, we can substitute it back into the second equation to find y:
y = 2(7) - 38
y = 14 - 38
y = -24
Therefore, the two numbers are:
x = 7
y = -24
The difference between two numbers is 31. The smaller number is 38 less than twice the larger number. Find the two numbers.(1 point)
1 answer