The diameter of the large piston of a hydrolic press is 20 cm,and the cross-sectional area of the small piston is 5cm².if the force of 400N is applied to the small piston,what is the resulting force exerted on the large piston?

Answer 1

We can use the principle of Pascal's Law which states that pressure applied to a fluid is transmitted uniformly in all directions. Therefore, the pressure applied to the small piston will be transmitted to the large piston, resulting in a larger force.

First, we need to find the pressure applied to the small piston:

Pressure = Force/Area

Pressure = 400N/5cm²

Pressure = 80N/cm²

Now, we can use this pressure to find the resulting force on the large piston:

Force = Pressure x Area

Force = 80N/cm² x π(10cm)²

Force = 80N/cm² x 100πcm²

Force = 8000πN

Therefore, the resulting force exerted on the large piston is approximately 25,132 N (8000π ≈ 25,132).