The diameter of a road roller is 140cm and its length is 2.2m. It takes 400 complete revolutions to move over to level a stretch of a road 2.2m wide find the surface area of stretch of road leveled in m sq.

Answer 1

area = (400)(pi)(1.4m)(2.2m) = 3870 m^2

Answer 2

diameter is 140cm
it 's not radius sir

Answer 3

that's why I showed the circumference as pi*d, and not 2pi * r

Still, thanks for checking my work.

Answer 4

I dont know how can we solve this question please help me and give me the answer of this question