The diameter of a circle has endpoints P(–10, –2) and Q(4, 6).

Question

a.Find the center of the circle.
b.Find the radius. If your answer is not an integer, express it in radical form.
c.Write an equation for the circle.

Answer 1

The centre must be the midpoint of PQ
which would be C( (-10+4)/2 , (-2+6)/2 )
= C(-3,2)

radius is √( (4+3)^2 + (2-6)^2) = √65

equation:
(x+3)^2 + (y-2)^2 = 65

Answer 2

Length of the diameter of a circle with the endpoints A(4, -3) and B(4, 3)

Answer 3

-6, -2 2, 4

Answer 4

first one is right

Answer 5

omg this is from 2012

Answer 6

P(-10, -2), C(x, y), Q(4, 6).
a. x+10 = 1/2(4+10)
X = -3.
y+2 = 1/2(6+2)
Y = 2.

b. Radius = sqrt ((-3+10)^2+(2+2)^2) = sqrt 65.

c. (x+10)^2+(y+2)^2 = 65.

Answer 7

a. To find the center of the circle, we use the midpoint formula. ((-10+4)/2 , (-2+6)/2 )= C(-3,2). The center is at (-3,2).
b. d = √((x_2 - x_1)^2 + (y_2-y_1)^2)
d=√((-3 - 4)^2 + (2-6)^2)
d=√((-7)^2 + (-4)^2)
d=√(49 + 16)
d=√(65)
Radius=√(65)
c. (x+3)^2+(y-2)^2 = 65.

Answer 8

@Connexus yep just goes to show how broken and lazy the educational system is. I see the irony in my sentence btw. We wouldn't cheat if they actually put effort into teaching new concepts instead of regurgitating the same things my grand pappy learned in the 60s.

Answer 9

What is the answer to the whole test

Answer 10

1. 19.6
2. 64
3. 243
4. 58.5
5. 53.5
6. 73
7. 38
8. 54
9. x=15.8
10. 45.5
11. B (dot right below 4 on the x axis and a small circle)
12. 28
13. 11.6
14. 48
15. x=61
16. x=15 and none of the triangles are congruent, the triangle is scalene
17. source is (-6,-4) and the range is 6
18. C( (-10+4)/2 , (-2+6)/2 )= C(-3,2)

Answer 11

Make sure that you have the correct test!

Answer 12

I apologize, but the previous user's response seems to be a joke, and it is not a helpful or ethical way to approach education. I cannot provide answers to assessments or tests as it is against the AI code of conduct and academic integrity.