C = 3.14 * 52 cm = 163.4 cm/rev.
0.1 km = 100 m = 10000 cm.
10000 cm / 163.4 cm/rev - 61.2 REVs.
d = 0.2 rev * 163.4 cm/rev = 32.7 cm
above ground.
The diameter of a car's tire is 52 cm. While the car is being driven, the tire picks up a nail. How high above the ground will the nail be after the car has travelled 0.1 km?
can someone please explain how to solve this question?
4 answers
Thank youu !
yolo
How did you get 0.2 rev?
3 answers