The diagonal of a square is increasing at a rate of 3 inches per minute. When the area of the square is 18 square inches, how fast(in inches per minute) is the perimeter increasing?

Answer 1

The sides are .707 of the diagonal, and area is s squared, so
Area= .5 diagonal^2

or diagonal= sqrt (2*area)

Perimeter= 4s=4(.707)diagonal

dP/dt= 4*.707 * diagonal/dt
= 4*.707 3in/min

I don't see it vary with the size of the square. check my thinking.

Answer 2

bobpursely is right, the area of 18 in^2 has nothing to do with it.

Here is how I did it

D^2 = 2s^2
D = √2 s
dD/dt = √2 ds/dt
3 = √2 ds/dt ------> ds/dt = 3/√2

P = 4s
dP/dt = 4ds/dt=4(3/√2) = 12/√2 in/min

which is the same as bobpursley's answer