Obviously the perimeter cannot be shorter than one of its sides.
2.1 is the length of each of its sides.
Now find the perimeter.
The diagonal of a square is 3 feet long. Find its perimeter.
My answer:
a^2+b^2=c^2
x^2+x^2=3^3
2x^2=9 divide both side by 2
x^2=4.5
x=√4.5
x=2.1 feet
Is this right?
2 answers
how can the perimeter be less than the diagonal?
you found one of the sides...the perimeter is all four
you found one of the sides...the perimeter is all four