The device shown below contains 2 kg of water. When the cylinder is allowed to fall 250 m, the temperature of the water increases by 1.4°C. Suppose 2 kg of water are added to the container and the cylinder is allowed to fall 750 m. What would the increase in temperature be in this case?

Answer 1

work (energy) is proportional to the height

doubling the amount of water will halve the temperature change

Δt = 1.4ºC * (750 m / 250 m) * [2 kg / (2 kg + 2 kg)]

Answer 2

The device shown below contains 2 kg of water. The cylinder is allowed to fall 800 m during which the temperature of the water increases by 2.4°C. Some amount of water is added to the container and the experiment is repeated. All other values remain constant. This time the temperature of the water increases by 1.2°C. How much water was added to the container?

Answer 3

same height ... half the temp. increase ... must be twice the amount of water