say we have a cubic piece of ice one centimeter on a side floating on water:
Ice volume = 1.000 cm^3
Ice mass = .917 g
so
mass of water displaced = .917 g
volume of water displaced = .917 g/1.03 g/cm^3
= .890 cm^3 which is the volume of ice below water surface
volume of ice above water = 1.000-.890 = .110 cm^3
so volume above water / volume below water
= 0.110/.890 = 0.123
The density of water of ice is 0.917gm/cm-3 and the density of sea water is 1.03gm/cm-3.calculate the ratio volume of ice outside to the volume of ice which is inside the sea water
1 answer