To determine the mass of gold that will have the same volume as 12 grams of silver, we first need to find the volume of the silver.
The formula to calculate volume from mass and density is:
\[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \]
- Calculate the volume of silver:
- Mass of silver = 12 g
- Density of silver = 10.49 g/cm³
\[ \text{Volume of silver} = \frac{12 \text{ g}}{10.49 \text{ g/cm}^3} \approx 1.144 \text{ cm}^3 \]
- Now we can use this volume to find the mass of gold that would occupy the same volume, using the density of gold:
- Density of gold = 19.32 g/cm³
Using the volume calculated:
\[ \text{Mass of gold} = \text{Volume} \times \text{Density} \] \[ \text{Mass of gold} = 1.144 \text{ cm}^3 \times 19.32 \text{ g/cm}^3 \approx 22.08 \text{ g} \]
Thus, the mass of gold that will have the same volume as 12 grams of silver is approximately 22.08 g, which closely aligns with the provided response 22.10 g.
Therefore, the correct answer is: 22.10 g.
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