Density is a measurement of mass per volume. In this example, density of silver is 1.050 x 10^4 kilogram per cubic meter (1 cubic meter silver would have 10500 kg mass).
You should solve for the volume of the ingot, then multiply by density to find mass.
ingot volume = 1.0 cm x 4.0 cm x 7.8 cm (1 dm = 10cm). = 54.6 cm^3. Since there are 1 million cm^3 in 1 m^3, 54.6 cm^3 multiplied by (1 m^3/1000000 cm^3) will give ingot volume in cubic meters, which is 5.46x10^-5 m^3 (0.0000546).
This volume x density looks like:
5.46x10^-5 m^3 x 1.050x10^4 kg/m^3 = 5.733x10^1 kg, which is also shown as 0.5733 kg.
The density of silver is 1.050×104 kg/m3.
What is the mass of a rectangular ingot of silver with dimensions 1.00 cm × 4.00 cm × 0.780 dm?
How do I get started? I really do not understand.
4 answers
Small correction...
For the final mass of silver, I intended to write 5.733x10^-1 kg, which is also shown as 0.5733 kg silver.
For the final mass of silver, I intended to write 5.733x10^-1 kg, which is also shown as 0.5733 kg silver.
1.00 cm x 4.00 cm x 7.80 cm is not 54.7 cc is it? more like 31.2 cc.
Good catch DrBob. Fat fingers on calculator. Another reminder to check work.