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The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 6.76 m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water?
2 answers
Di + Db = Dsw
917 + Db = 1025 kg/m^3
Db = 108 kg/m^3 = Density of the bear.
Mass of bear = 6.76m^3*108kg/m^3=730 kg
Wt. of bear = 730kg * 9.8N/kg = 7154 N.
917 + Db = 1025 kg/m^3
Db = 108 kg/m^3 = Density of the bear.
Mass of bear = 6.76m^3*108kg/m^3=730 kg
Wt. of bear = 730kg * 9.8N/kg = 7154 N.