The density of ice is 917 kg/m3, and the density of sea water is 1025 kg/m3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 4.41 m3. What is the weight of the heaviest bear that the ice can support without sinking completely beneath the water? please help!

Answer 1

Vb = (Do/Df)*Vo,
Vb = (917/1025) * 4.41 = 3.95 m^3.

(917+Db)/1025 = 1,max.
917 + Db = 1025,
Db = 1025 - 917 = 108 kg/m^3 = Density of bear.

Wb = 108kg/m^3 * 4.41m^3 * 9.8N/kg =
4668 N.

Answer 2

NOTE:
Do = Density of object(ice).
Df = Density of fluid.
Db = Density of bear.