The density of gold is 19 times that of water. If you take a gold crown weighing 32 N and submerge it in water, how much upward force must you exert on the submerged crown to keep it from accelerating?

Answer 1

ρ(g)=19•ρ(w).
The buoyance force F =ρ(w) •V•g= =ρ(g)•V•g/19.
The weight of the crown
W = ρ(g)•V•g = 32 N =>
ρ(g)•V•g/19=32/19 =1.68 N.

Upward force =W-F=32 – 1.68 =30.32 N

Answer 2

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