mass = volume x density.
Substitute for mass and density; solve for volume. Make sure the units of density (you don't list that) agrees with the unit you want in the answer.
The density of dry air measured at 25 degrees Celsius is 1.19x10 to the negative 3rd power. What is the volume of 50.0g of air?
9 answers
can u explain that a little more because i still don't understand
There isn't anything to explain.
mass = volume x density. That's the formula. That's it. End of story. You read the problem, substitute the numbers, solve the equation.
mass in the problem = 50g
density in the problem = 1.19E-3. You don't list the units. I will assume for purposes of showing you that this is 1.18E-3 g/mL. If it is some other unit you will need to adjust that.
Substitute.
mass = volume x density
50 = volume(in mL) x 1.19E-3 g/mL
volume = 50/1.19E-3 = about 42000 mL.
If you will explain what trouble you are having perhaps I can focus on a better answer.
mass = volume x density. That's the formula. That's it. End of story. You read the problem, substitute the numbers, solve the equation.
mass in the problem = 50g
density in the problem = 1.19E-3. You don't list the units. I will assume for purposes of showing you that this is 1.18E-3 g/mL. If it is some other unit you will need to adjust that.
Substitute.
mass = volume x density
50 = volume(in mL) x 1.19E-3 g/mL
volume = 50/1.19E-3 = about 42000 mL.
If you will explain what trouble you are having perhaps I can focus on a better answer.
50/.00119=42016.8067227mL>>then you have to round to 2 significant digits b/c 50 has 2 sig figs which is the least # of sig figs
50/.00119=42016.8067227mL>>then you have to round to 2 significant digits b/c 50 has 2 sig figs which is the least # of sig figs, so its 42,000mL
sma
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d33z n_u_ts in yo Face D1_ick Sucker!
the answe iri sf
3 answers