The density of aluminum is 2.70g/cm3. If a cube of aluminum weighs 13.5 grams whatis the length of the edge of the cube. I need help with the formula to figure this one out.

Answer 1

mass = volume x density
Solve for volume.
Then, since this is a cube, the length, width, and height are equal. So
volume = L x W x H but since L = W = H, then
volume = L x L x L. Solve for L.

Answer 2

Hello Dr Bob,, I am still a little confused is this what it will look like 13.5/2.70=5 then take 5*5*5=125

Answer 3

Close but no cigar.
Volume = mass/density = 13.5/2.7 = 5.0 cc whis is ok to this point. Now,
volume = L x L x L
5 = L x L x L
5 = L³; therefore,
L = cube root 5 OR

L = 5^1/3
(On your calculator, enter 5, then punch the y^x button, and type in .33333 (which is 1/3) and = to find the answer of 1.70997 which rounds to 1.71 cm to three significant figures.

Answer 4

Thank you DR Bob

Answer 5

81 g

Answer 6

Aluminum has a density of 2.7 g/mL. What is the volume of an aluminum Cube that has a mass of 12.7 grams

Answer 7

mass = volume x density
since this is a cube the length,width and height are
equal so volume =L ×W×H but since L=W=H
volume = mass/density
= 12,7÷2,7

= 4,703703704
4,703703704 = L^3
L = 1,675508565cm

Answer 8

I need help with d first chemistry question on thi page