The density of a gas is 1.96 g L–1 at 1.00 atm and 0

°C. What is the density of this gas at 0.855 atm and 25.0
C?

3 answers

Two ways to do this. The long way, but easier to explain, and the short way but harder to explain. The long way first:
The general gas formula can be modifed to
P*M = dRT where M is molar mass and d is density in g/L. Substitute into that and solve for M. Then use the same equation, substitute the new conditions and solve for the new density.

Shorter way.
1.96 x (pres factor) x (Temp factor) =
1.96 g/L x (0.855/1) x (273/298) = ?
How does the shorter way work?
P factor. P decreases therefore L increases and density gets smaller so the factor must be less than 1 which makes the small number go in the numerator.
T factor. T increases from 273 to 298, L must increase, larger L means smaller density so the T factor must be less than 1 which makes the small number go on top.
1.8
I'm sorry, I need more information in order to help you. What is your question?