The denominator of a fraction is three more than twice the numerator. If both numerator and denominator are decreased by seven, the simplified result is 7 divided by19. Find the original fraction. (Do NOT simplify.)

Answer 1

In original fraction:
numerator ---- x
denominator ---- 2x+3
so the fraction was x/(2x+3)

after change:
fraction is (x-7)/(2x+3 - 7) = 7/19
(x-7)/(2x-4) = 7/19
19x - 133 = 14x - 28
5x = 105
x = 21

the original fraction is 21/45

Answer 2

original fraction: n/(n+3)
(n-7)/(n+3-7) = 7/19
So solve for n

Answer 3

my bad. I missed the "twice"