the dencity of 3 molal solution of NaOH is 1.110g/mL calculate the molarity of the solution

Answer 1

Note the correct spelling of density. Probably a typo.
3 m = 3 mols/kg solvent.
molar mass NaOH = 40 grams; therefore, 3 mols = 120 grams.
The solution is 1000 g solvent + 120 g NaOH = total of 1000+120 = 1120g.
Use density to convert to volume in mL and convert to L, then M = mols/L soln.

Answer 2

Density = Mass/Volume
Volume = 40/1.110
V = 36.03 ml
M = 120/40 * 1000/36.03
M = 83.26 M